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Home/ Questions/Q 6253135
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:56:05+00:00 2026-05-24T13:56:05+00:00

I’m trying to implement a piece of code to synchronously start looped service in

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I’m trying to implement a piece of code to synchronously start looped service in Java. The idea is, code under // STARTER comment should be considered as piece of Service.go() method, so if service fails to start, I want to re-throw the exception synchronously. That piece of code should only finish in case I’ve tried to start the thread, waited until its execution flow reached some point and next, if there are no problems, my go() method quits and thread goes on, or, if there were problems, I can re-throw the exception caught in thread’s run() method from my go() method. Here’s the solution that seems to work fine, but I’m curious if it’s possible to make it a couple times shorter 🙂

public class Program {

private static boolean started;
private static Throwable throwable;

public static void main(String[] args) {
    final Object startedSetterLock = new Object();

    Thread thread = new Thread() {
        public void run() {
            System.out.printf("trying to start...\n");

            boolean ok;
            Throwable t = null;
            try {
                init();
                ok = true;
            } catch(Exception e) {
                ok = false;
                t = e;
            }

            synchronized(startedSetterLock) {
                started = ok;
                throwable = t;
                startedSetterLock.notifyAll();
            }

            if(!ok) {
                return;
            }

            while(true) {
                try {
                    System.out.printf("working...\n");
                    Thread.sleep(1000);
                } catch(InterruptedException e) {
                    System.out.printf("interrupted\n");
                }                   
            }
        }

        private void init() throws Exception { throw new Exception(); } // may throw
    };

            // STARTER
    synchronized(startedSetterLock) {
        thread.start();
        try {           
            startedSetterLock.wait();
        } catch(InterruptedException e) {
            System.out.printf("interrupted\n");
        }
    }       

    // here I'm 100% sure that service has either started or failed to start
    System.out.printf("service started: %b\n", started);
    if(!started) {
        throwable.printStackTrace();
    }
}
}

And also, there’s a reason to have initialization code executed within that thread, so, please, don’t advise running initialization code explicitly in go() method and then just passing all the stuff to the thread.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:56:06+00:00Added an answer on May 24, 2026 at 1:56 pm

    How about overriding the Thread.start() method?

    public static void main(String[] args) {
        Thread t = new Thread() {
            public void run() {
                while (true) {
                    try {
                        System.out.printf("working...\n");
                        Thread.sleep(1000);
                    } catch (InterruptedException e) {
                        System.out.printf("interrupted\n");
                    }
                }
            }
    
            @Override
            public synchronized void start() {
                try {
                    init();
                } catch (Exception e) {
                    throw new RuntimeException(e);
                }
                super.start();
            }
    
            private void init() throws Exception {
                throw new Exception("test");
            }
        };
    
        t.start();
    }
    
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