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Home/ Questions/Q 3485656
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T10:56:02+00:00 2026-05-18T10:56:02+00:00

I’m trying to implement a web service which accepts a list of strings, each

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I’m trying to implement a web service which accepts a list of strings, each of which is a regular expression. These need to be compared against six columns of a database, and any rows which match need to be returned.

I believe Oracle has a regexp_like() function which I might be able to use, but I’m looking for the best way to do this using Hibernate, so I’m not working against the persistence engine.

I started with something like this, in which the participants collection contains the regular expressions:

List<Message> messages = new ArrayList<Message>();
List<Message> m1 = ((Session) entityManager.getDelegate())
    .createCriteria(MessageSSR.class).add(Restrictions.or(
            Restrictions.in("Node2Id", participants),
            Restrictions.in("Node2Id", participants))).list();
List<Message> m2 = ((Session) entityManager.getDelegate())
    .createCriteria(MessageSSR.class).add(Restrictions.or(
            Restrictions.in("Node3Id", participants),
            Restrictions.in("Node4Id", participants))).list();
List<Message> m3 = ((Session) entityManager.getDelegate())
    .createCriteria(MessageSSR.class).add(Restrictions.or(
            Restrictions.in("Node5Id", participants),
            Restrictions.in("Node6Id", participants))).list();
messages.addAll(m1);
messages.addAll(m2);
messages.addAll(m3);

This doesn’t work because “in” won’t do what I want, and this does not appear to tell Hibernate to use a regular expression match.

This is the only answer I’ve come up with, but it looks really ugly:

List<Message> messages = new ArrayList<Message>();
for (String re : participants) {
    List<Message> m1 = ((Session) entityManager.getDelegate())
        .createCriteria(MessageSSR.class)
        .add(Restrictions.or(
                Restrictions.sqlRestriction("regexp_like(NODE_1, " + re + ")"),
                Restrictions.sqlRestriction("regexp_like(NODE_2, " + re + ")")
        )).list();
    List<Message> m2 = ((Session) entityManager.getDelegate())
        .createCriteria(MessageSSR.class)
        .add(Restrictions.or(
                Restrictions.sqlRestriction("regexp_like(NODE_3, " + re + ")"),
                Restrictions.sqlRestriction("regexp_like(NODE_4, " + re + ")")
        )).list();
    List<Message> m3 = ((Session) entityManager.getDelegate())
        .createCriteria(MessageSSR.class)
        .add(Restrictions.or(
                Restrictions.sqlRestriction("regexp_like(NODE_5, " + re + ")"),
                Restrictions.sqlRestriction("regexp_like(NODE_6, " + re + ")")
        )).list();
    messages.addAll(m1);
    messages.addAll(m2);
    messages.addAll(m3);
}

I’m trying to push as much of this over to Oracle as I can. This appraoch seems likely to work, but putting the restrictions in without using parameters means I’m losing a lot of potential efficiency. Can anyone see a better way to do this? For simplicity, I’m trusting the regular expressions that are being passed to me.

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  1. Editorial Team
    Editorial Team
    2026-05-18T10:56:02+00:00Added an answer on May 18, 2026 at 10:56 am

    There’s nothing in the hibernate docs for performing regular expression queries (using HQL or Criteria queries). The approach using the sqlRestrictions should probably be changed to one of the overloaded methods to avoid a SQL Injection vulnerability.

    Example code:

    Restrictions.sqlRestriction("regexp_like({alias}.NODE_1, ?)", re, Hibernate.STRING)
    
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