Question

I’m trying to implement jQuery Flare Video Plugin for my website.. There’s a dropdown menu which the user must choose a year from, when the submit button is clicked, a video is meant to show on the screen. I have a database that grabs the path to the video from the database i.e $row['videoName'] .
My question is how can I pass PHP variables in jQuery function.. In the example given in the plugin a full path to the video was given insrc attribute of jQuery function. I’m trying to make the src dynamic by passing the PHP Variable into it.

I’m not getting any error, and the div containing the video appears on the screen, but the video does not show.

Thank you.

    jQuery(function($){
          fv = $("#video").flareVideo();
          fv.load([
            {
              src:  '$row['videoName']',
              type: 'video/mp4'
            }
          ]);
        })
      </script>

Answer 1

To access the PHP variable you must enclose the code in PHP brackets like so:

jQuery(function($){
    fv = $("#video").flareVideo();
    fv.load([
      {
        src:  "<?php echo $row['videoName']; ?>",
        type: 'video/mp4'
      }
    ]);
  })
</script>

This must also be on the same page as the PHP variable is created to allow access.