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Home/ Questions/Q 7824099
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T08:29:06+00:00 2026-06-02T08:29:06+00:00

I’m trying to implement retry logic with exponential backoff using NSTimer. My code looks

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I’m trying to implement retry logic with exponential backoff using NSTimer.
My code looks like this:

-(void)start
{
  [NSTimer scheduledTimerWithTimeInterval:0.0 target:self
    selector:@selector(startWithTimer:) userInfo:nil repeats:NO];
}

-(void)startWithTimer:(NSTimer *)timer
{
  if (!data.ready) {
    // timer.timeInterval == 0.0 ALWAYS!
    NSTimeInterval newInterval = timer.timeInterval >= 0.1 ? timer.timeInterval * 2 : 0.1;
    newInterval = MIN(60.0, newInterval);
    NSLog(@"Data provider not ready. Will try again in %f seconds.", newInterval);
    NSTimer * startTimer = [NSTimer scheduledTimerWithTimeInterval:newInterval target:self
        selector:@selector(startWithTimer:) userInfo:nil repeats:NO];
    // startTimer.timeInteval == 0.0 ALWAYS!
    return;
  }

  ...
}

The problem I’m having is that the timer NSTimer scheduledTimerWithTimeInterval seems to ignore the interval I’m providing and always sets it to 0.0. Any suggestions on what I’m doing wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T08:29:07+00:00Added an answer on June 2, 2026 at 8:29 am

    The Apple Documentation has this to say about the timeInterval property on NSTimer.

    https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/nstimer_Class/Reference/NSTimer.html

    If the receiver is a non-repeating timer, returns 0 (even if a time interval was set).

    You will need to use some other means to keep track of what the timer interval should be. I recommend an iVar on your class.

    -(void)start
    {
      _timeInterval = 0.0;
      [NSTimer scheduledTimerWithTimeInterval:_timeInterval target:self
        selector:@selector(startWithTimer:) userInfo:nil repeats:NO];
    }
    
    -(void)startWithTimer:(NSTimer *)timer
    {
      if (!data.ready) {
        _timeInterval = _timeInterval >= 0.1 ? _timeInterval * 2 : 0.1;
        _timeInterval = MIN(60.0, _timeInterval);
        NSLog(@"Data provider not ready. Will try again in %f seconds.", _timeInterval);
        NSTimer * startTimer = [NSTimer scheduledTimerWithTimeInterval:_timeInterval target:self
            selector:@selector(startWithTimer:) userInfo:nil repeats:NO];
        return;
      }
    
      ...
    }
    
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