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Home/ Questions/Q 8519629
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T06:18:10+00:00 2026-06-11T06:18:10+00:00

I’m trying to implement the equivalent of the Linux macro ACCESS_ONCE in c++11. ACCESS_ONCE(x)

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I’m trying to implement the equivalent of the Linux macro ACCESS_ONCE in c++11.
ACCESS_ONCE(x) takes the address of x, casts to a pointer to a volatile of the same type as x, then dereferences it. This forces the compiler to not optimize out accesses to x through this macro (and make the access occur only once here).

My attempt to do it in c++11 involves decltype:

#define ACCESS_ONCE(x) (*static_cast<decltype(x) volatile *>(&(x)))

This works for most cases but I use it once like so:

void foo(void **bar) {
  while (ACCESS_ONCE(*bar) != NULL)
    ;
}

This fails with an error:

'volatile' qualifiers cannot be applied to 'void*&'

What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-06-11T06:18:11+00:00Added an answer on June 11, 2026 at 6:18 am

    Change the macro to this:

    #define ACCESS_ONCE(x) (*static_cast<std::remove_reference<decltype(x)>::type volatile *>(&(x)))
    

    Dereferencing a pointer results in a reference. The macro is trying to cast it to a void *& volatile instead of a void * volatile like you want. You can’t apply the volatile qualifier to a reference type so you have to use std::remove_reference to change it to the normal non-reference type.

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