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Home/ Questions/Q 7006729
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:30:54+00:00 2026-05-27T21:30:54+00:00

I’m trying to initialize a dict variable but I don’t understand why one way

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I’m trying to initialize a dict variable but I don’t understand why one way works, while the other does not.

In case 1 everything is alright and I can use dict later.
In case 2 it will be released very soon (It will becomes a zombie) and If I try to use it later (outside a block) the program crashes.

Here’s some code from my class (c++ mixed with objective-c) written for ios.
Inside the block i tried to initialize variable dict in two different ways.

class Data
{
public:
    NSMutableDictionary *dict;

    void DoSomeStuff()
    {
    [NSSomeFrameworkTool doSomeStuffWithCompletionHandler:^(NSError *err) {
        // case 1 - OK
        dict = [[NSMutableDictionary alloc] initWithDictionary:[NSKeyedUnarchiver unarchiveObjectWithFile:@"dict.dat"]];

        // case 2 - will crash later if i try to use dict
        dict = [NSKeyedUnarchiver unarchiveObjectWithFile:@"dict.dat"];   }];
    }
}

This class has class variable dict, which is initialized in the DoSomeStuff() method.
That method calls a method from the ios framework that uses block (as a callback) to inform me that some task is done.

I was wondering why case 1 and case 2 work different. Maybe it is forbidden to use references outside the block, that was initialized inside this block?
What’s wrong with doing this the way shown in case2?

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:30:55+00:00Added an answer on May 27, 2026 at 9:30 pm

    In first case you don’t release your dict, and in second case it is autoreleased so you should retain it.

    dict = [[NSKeyedUnarchiver unarchiveObjectWithFile:@"dict.dat"] retain];
    
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