Question

I’m trying to insert array into database. Why don’t this work?

$array_zone = array();
$array_data = array();
while($row = mysql_fetch_array($keputusan1)){
$array_zone[] = $row['zone'];
$array_data[] = $row['data'];
}

echo "<pre>";
print_r($array_zone);
echo "<br>";
print_r($array_data);
echo "</pre>";

$list_zone = implode(",", $array_zone);
$list_data = implode(",", $array_data);

for($i = 0; $i < 4; $i++)
{
mysql_query("INSERT INTO `db`.`table1` (`id`, `domain`) VALUES ('$list_zone', '$list_data')");
}

Array output before implode:

Array
(
    [0] => 270
    [1] => 270
    [2] => 255
    [3] => 255
)

Array
(
    [0] => ok.com.
    [1] => lo.com.
    [2] => i.com.
    [3] => k.com.
)

Result I’m getting:

0 key should go with data in 0 key and 1 key should go with data in 1 key and so on… Help me please. Thank you.

Answer 1

You can use INSERT … SELECT. The result returned in $keputusan1 is a SELECT query. And it certainly returns zone and data columns. Say the query is SELECT zone, data, columns ... FROM tbl1.

If you use INSERT … SELECT the new query would be

INSERT INTO `db`.`table1` (`id`, `domain`) SELECT zone, data FROM tbl1";

This will SELECT first then INSERT it in one shot.

The problems with your code are

1. 4 SQL statements. It should be 1.
2. You should use $array_zone and $array_data instead of $list_zone and $list_data if for loop is used. But it should not be as of step 1.