Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4253514
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T04:57:22+00:00 2026-05-21T04:57:22+00:00

i’m trying to join 3 tables together but use an IF statment to only

  • 0

i’m trying to join 3 tables together but use an IF statment to only run a certain query

I have a user table, customer and staff table. The first part below works:

SELECT user.`userID`, `username`,  `user`.email, `registeredBy`, `registeredDate`, 
  CONCAT(staff.firstName, ' ' ,staff.lastName) AS staffName FROM `user` 
   INNER JOIN `level` ON `user`.levelID = `level`.levelID 
    INNER JOIN `staff` ON `user`.registeredBy = `staff`.userID 

I need to view who registered the user which shows fine, but then I need to view either the staff name if the user level is 2 or the customer name if the user level is 1

INNER JOIN `staff` ON `user`.userID = staff.userID IF (user.level = 2)
INNER JOIN `customer` ON user.userID = customer.userID IF(user.level = 1)   

Add the above creates the error

Not unique table/alias: ‘staff’

If I remove the inner join for staff I then get the error

You have an error in your SQL syntax;
check the manual that corresponds to
your MySQL server version for the
right syntax to use near
‘IF(user.level = 2)’ at line 6

I need to only show the customer name or the staff name depending on the level, but I cannot understand how as I am joing the staff table twice. Once to get the memeber of staff who registered the user and then to view the staff name(or customer).

To help make things easier an example of the page I am displaying is:

username | name | account type |
registered by

Hope I haven’t made it too confusing to understand.

Thanks.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-21T04:57:22+00:00Added an answer on May 21, 2026 at 4:57 am
    Select user.userID
        , username
        , user.email
        , registeredBy, registeredDate
        , Case 
            When User.Level = 2 Then Concat(Level2Staff.firstName, ' ' , Level2Staff.lastName) 
            When User.Level = 1 Then Concat(customer.firstName, ' ' , customer.lastName) 
            End
            AS staffName 
    FROM user
        Inner Join level
            On user.levelID = level.levelID 
        Inner Join staff
            On user.registeredBy = staff.UserID
        Left Join customer
            On customer.userID = user.UserID
                And user.level = 1
        Left Join staff As Level2Staff
            On user.userID = Level2Staff.UserID
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to understand how to use SyndicationItem to display feed which is
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I want to count how many characters a certain string has in PHP, but
I have a French site that I want to parse, but am running into
I want use html5's new tag to play a wav file (currently only supported
I would like to run a str_replace or preg_replace which looks for certain words
This could be a duplicate question, but I have no idea what search terms
I'm trying to convert HTML to plain text. I get many &\#8217; &\#8220; etc.
I'm trying to use string.replace('’','') to replace the dreaded weird single-quote character: ’ (aka
I am trying to loop through a bunch of documents I have to put

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.