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Home/ Questions/Q 8668923
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T18:20:04+00:00 2026-06-12T18:20:04+00:00

I’m trying to learn and advance with SQLAlchemy. Today I wanted to learn about

  • 0

I’m trying to learn and advance with SQLAlchemy. Today I wanted to learn about exceptions it raises.

I’m working on a Pyramid based project, MySQL server (InnoDB) and SQLAlchemy.

I am trying to except all errors since NoResultFound error would not raise or print in console. So I except exc.SQLAlchemyError.

When I query my table and no results are found, it does not raise or catch or except anything whatsoever and continues operating.

Questions:

  1. How can I and How should I query for .all() or .one(), and deal with
    the issue of not having any rows returned?
  2. How can I and how should I deal with others SQL or System related errors? I would like to record them and observe them to fix issues.

My code is:

try:
    query = Session.query(MyTable).filter(Terms.column == my_string).all()
except exc.SQLAlchemyError, e:
    print e
    return False

(Instead of exc.SQLAlchemyError, I first tried NoResultFound, e)

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  1. Editorial Team
    Editorial Team
    2026-06-12T18:20:06+00:00Added an answer on June 12, 2026 at 6:20 pm

    Indeed this code will not raise an exception if no records are found. So instead you should throw your own exception:

    import logging
    try:
        records = Session.query(MyTable).\
            filter(Terms.column == my_string).all()
        if len(records) == 0:
            raise MyException('No records found')
    except MyException, e:
        logging.info('No records found')
    except exc.SQLAlchemyError, e:
        logging.exception('Some problem occurred')
    
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