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Home/ Questions/Q 6816129
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:53:20+00:00 2026-05-26T20:53:20+00:00

I’m trying to learn assembly (Intel x86 with NASM on Linux) and unsurprisingly I’m

  • 0

I’m trying to learn assembly (Intel x86 with NASM on Linux) and unsurprisingly I’m having some trouble.

The following is meant to take a buffer of text, remove all spaces and put the result in another buffer. It’s part of a larger project I’m doing as a way to learn, and I’m developing each part individually first. In the actual project the message is going to come from a file, here I’m just using a hardcoded string (Msg) for testing purposes.

But it’s not working. I’ve been fiddling with it for a while now, but I’m sure I’ve missed some fundamental concept somewhere or something.

[SECTION .data]
Msg   db '    %d Whitespace, thanks      ', 10, 0

[SECTION .bss]
BUFFSIZE   equ 80 
BufferA    resb BUFFSIZE
BufferB    resb BUFFSIZE

[SECTION .text]
extern printf

global main

; PROCEDURE stripwhite
; INPUT     None
; OUTPUT    None
; NOTES     Strips all leading and trailing whitespace from BufferA
;           Result is stored in BufferB
stripwhite:
    pushad                  ; Save caller's registers

    mov eax, BufferA        ; Source string
    mov ebx, BufferB        ; Output string
    .loop:
        mov cl, byte [eax]  ; Get a single character from the source
        cmp cl, 0
        je .end             ; End if character is null
        cmp cl, 32
        jne .save           ; Save it if it's not a space
        add eax, 1          ; Otherwhise skip to next character
        jmp .loop
    .save:
        mov byte [ebx], cl  ; Save character in output buffer
        add eax, 1          ; Move on to next character
        add ebx, 1
        jmp .loop
    .end:
        mov byte [ebx], 0   ; Add a null at the end

    popad                   ; Restore caller's registers
    ret

main:
    push ebp                ; Set up stack frame for debugger
    mov ebp, esp
    push ebx                ; Must preserve ebp, ebx, esi and edi
    push esi
    push edi
    ; start

    mov dword [BufferA], Msg
    call stripwhite

    push 0
    push BufferB            ; Push message string
    call printf             ; Print line count
    add esp, 8              ; Clean up the stack

    ; end
    pop edi                 ; Restore saved registers
    pop esi
    pop ebx
    mov esp, ebp            ; Destroy stack frame
    pop ebp
    ret

I’m kinda wondering why it seems I have to use dword in the line before call stripwhite above when both Msg and the two buffers use bytes, but the linker (called by GCC in this case) throws an error when I use anything else:

stripwhite.o:stripwhite.asm:82: relocation truncated to fit: R_386_8 against `.data'
collect2: ld returned 1 exit status

Maybe that has something to do with it, but I can’t figure out what.

The following seems to work just fine, and it’s basically identical except the code is not inside a procedure.

[SECTION .data]
Msg   db '    %d Whitespace, thanks      ', 10, 0

[SECTION .bss]
BUFFSIZE   equ 80 
BufferA    resb BUFFSIZE
BufferB    resb BUFFSIZE

[SECTION .text]
extern printf

global main

main:
    push ebp                ; Set up stack frame for debugger
    mov ebp, esp
    push ebx                ; Must preserve ebp, ebx, esi and edi
    push esi
    push edi
    ; start

    mov eax, Msg
    mov ebx, BufferB
    .loop:
        mov cl, byte [eax]
        cmp cl, 0
        je .end
        cmp cl, 32
        jne .save
        add eax, 1
        jmp .loop
    .save:
        mov byte [ebx], cl
        add eax, 1
        add ebx, 1
        jmp .loop
    .end:
        mov byte [ebx], 0

    push 0
    push BufferB            ; Push message string
    call printf             ; Print line count
    add esp, 8              ; Clean up the stack

    ; end
    pop edi                 ; Restore saved registers
    pop esi
    pop ebx
    mov esp, ebp            ; Destroy stack frame
    pop ebp
    ret
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  1. Editorial Team
    Editorial Team
    2026-05-26T20:53:21+00:00Added an answer on May 26, 2026 at 8:53 pm
    [SECTION .bss]
    BUFFSIZE   equ 80 
    BufferA    resb BUFFSIZE
    BufferB    resb BUFFSIZE
    

    BufferA is an array.

    mov dword [BufferA], Msg
    

    This is putting the address of Msg in the first 4 bytes of BufferA, probably not what you want. You could call memcpy instead.

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