Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6380379
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T02:15:38+00:00 2026-05-25T02:15:38+00:00

I’m trying to learn some Template Haskell. As an exercise, I wrote a function

  • 0

I’m trying to learn some Template Haskell. As an exercise, I wrote a function that can generate things like isLeft and isRight (inspired by this question). Here’s my humble attempt:

isA connam = do
    ConE nam <- connam
    nn <- newName "p"
    lamE [varP nn] $ caseE (varE nn) [
                       match (conP nam [wildP]) ( normalB [| True |] ) [],
                       match wildP ( normalB [| False |] ) [] 
                     ]

The problem is that I have to write $(isA [| Left |]) instead of the more intuitive isA Left. Is it possible to get rid of the ugly syntax? I can’t seem to find the answer in the documentation.

The function only works with one-argument constructors, but this is for another question.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T02:15:39+00:00Added an answer on May 25, 2026 at 2:15 am

    The syntax is there for a reason; to inform the reader that there is compile-time magic going on here. You can only eliminate the $(...) when your splice is at the top level.

    However, we can eliminate the [| ... |] and also make the code more type-safe by taking in a Name instead of an Exp:

    isA nam = do
        nn <- newName "p"
        lamE [varP nn] $ caseE (varE nn) [
                           match (conP nam [wildP]) ( normalB [| True |] ) [],
                           match wildP ( normalB [| False |] ) [] 
                         ]
    

    To use this, you’d write $(isA 'Left), which is a little easier on the eyes.

    As a bonus, if you try giving it something other than a Name, you get a type error instead of an irrefutable pattern match error.

    See also: Template Haskell Syntax

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

For some reason, after submitting a string like this Jack’s Spindle from a text
I've got a string that has curly quotes in it. I'd like to replace
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I need a function that will clean a strings' special characters. I do NOT
I'm trying to create an if statement in PHP that prevents a single post
I have some data like this: 1 2 3 4 5 9 2 6
I am trying to understand how to use SyndicationItem to display feed which is
Basically, what I'm trying to create is a page of div tags, each has
I'm new to using the Perl treebuilder module for HTML parsing and can't figure
link Im having trouble converting the html entites into html characters, (&# 8217;) i

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.