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Home/ Questions/Q 7826203
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T09:18:16+00:00 2026-06-02T09:18:16+00:00

I’m trying to left join the same table twice but it’s giving me some

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I’m trying to left join the same table twice but it’s giving me some problems. I have two tables ee_all and ee_calendar_events that I want to join.

SELECT
    u.first_name,
    u.last_name,
    u.email,
    SUM(e1.total_vacation_hours_earned) AS vacation_hours_earned,
    SUM(e2.absent_hours)
FROM ee_all AS u 
LEFT JOIN ee_calendar_events AS e1 ON u.user_id = e1.sched_user_id
LEFT JOIN ee_calendar_events AS e2 ON u.user_id = e2.sched_user_id AND e2.event_id = 2
WHERE
    u.user_id = 23

The vacation_hours_earned column is supposed to return 133, which it does if I take out the second join. But soon as I add it, the query takes forever and the vacation_hours_earned has a value of 2000 or something (which is wrong). My guess is it’s summing the row again when I add the second join, but I don’t wan’t that. I’ve been trying for a few hours but can’t find a way around it, would appreciate any help.

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  1. Editorial Team
    Editorial Team
    2026-06-02T09:18:17+00:00Added an answer on June 2, 2026 at 9:18 am

    When the rightmost table (the second join) has more than one row corresponding to a row of the table expression to the left, rows of the left-hand table expression are duplicated and count more than once in the SUM. Use subqueries instead.

    SELECT
        u.first_name,
        u.last_name,
        u.email,
        (
            SELECT
                SUM(e1.total_vacation_hours_earned)
            FROM
                ee_calendar_events AS e1
            WHERE
                u.user_id = e1.sched_user_id
        ) AS vacation_hours_earned,
        (similar) AS absent_hours
    FROM
        ee_all AS u
    WHERE
        u.user_id = 23
    
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