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Home/ Questions/Q 7916389
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T14:47:24+00:00 2026-06-03T14:47:24+00:00

I’m trying to make a deploy command in my Makefile, which simply overwrites to

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I’m trying to make a deploy command in my Makefile, which simply overwrites to the branch deployment and then pushes this branch to origin.

However, the command must stop/fail with an error message when the working tree is not empty.

Something like the following:

deploy:

    status=$(git status --porcelain)
    test "x$(status)" = "x"
    git branch -f deployment
    git push origin deployment

Unfortunately, this test on and status variable do not seem to function as wanted.

How would one achieve this? Am I indeed supposed to use test?

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  1. Editorial Team
    Editorial Team
    2026-06-03T14:47:27+00:00Added an answer on June 3, 2026 at 2:47 pm

    Use git diff-index to check if the repo is dirty:

    deploy:
            git diff-index --quiet HEAD 
            git branch -f deployment
            git push origin deployment
    

    If you want to check shell variables in a makefile, you need to ensure that you check the value of the variable in the same shell as the one in which it is set. Make will invoke each command in a separate shell, so you would need to do something like:

    deploy:
            @status=$$(git status --porcelain); \
            if test "x$${status}" = x; then \
                git branch -f deployment; \
                git push origin deployment; \
            else \
                echo Working directory is dirty >&2; \
            fi
    

    Note the double ‘$’, the semi-colon, and the line continuations.

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