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Home/ Questions/Q 8451343
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T11:12:49+00:00 2026-06-10T11:12:49+00:00

I’m trying to make a function which will do what the following statements do….

  • 0

I’m trying to make a function which will do what the following statements do….

<?php
if(isset($var)){
    echo $var;
}
else {
    echo "";
}
?>

I have done this so far….

<?php
function echo_ifset($dyn_var){
    $var = $dyn_var;
    if(isset($$var)){
        global $$var;
        echo $$var;
    }
}

but its not displaying anything when I run..

echo_ifset('message');
// while message is a defined variable.
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T11:12:51+00:00Added an answer on June 10, 2026 at 11:12 am

    If you work with a reference, you won’t have any problems with warnings (or errrors, my PHP is a little rusty!) if the variable isn’t defined:

    function echo_ifset(&$var) { 
        if (isset($var)) { 
            echo $var; 
        };
    }
    

    Note the & before the $var declaration, this is the reference operator.

    Then, you can just call it using:

    echo_ifset($message);
    

    This method is also great if you want to define a method to set a default value:

    <?php 
    function defaultValue(&$var, $default) { 
        if (!isset($var)) { 
            return $default; 
        }
    
        return $var;
    } 
    ?>
    

    Some extra reading material can be found at: http://www.php.net/manual/en/language.references.pass.php

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