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Home/ Questions/Q 8900253
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T01:03:46+00:00 2026-06-15T01:03:46+00:00

I’m trying to make a markdown parser in python, not because it’s useful but

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I’m trying to make a markdown parser in python, not because it’s useful but because it’s fun and because I’m trying to learn regular expression.

#! /usr/bin/env python
#-*- coding: utf-8 -*-

import re

class Converter:

    def markdown2html(self, string):

        string = re.sub('\*{3}(.+)\*{3}', '<strong>\\1</strong>', string)
        string = re.sub('\*{2}(.+)\*{2}', '<i>\\1</i>', string)
        string = re.sub('^#{1}(.+)$', '<h1>\\1</h1>', string, flags=re.MULTILINE)
        string = re.sub('^#{2}(.+)$', '<h2>\\1</h2>', string, flags=re.MULTILINE)

        return string

markdown_sting = """
##h2 heading
#H1 heading
This should be a ***bold*** char
#anohter h1
anohter ***bold***
this is a **italic** string
"""

converter = Converter()
print converter.markdown2html(markdown_sting)

It prints

<h1>#h2 heading</h1>
<h1>H1 heading</h1>
This should be a <strong>bold</strong> char
<h1>anohter h1</h1>
anohter <strong>bold</strong>
this is a <i>italic</i> string

As you can see it does not parse the h2 tag. Where I went wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T01:03:48+00:00Added an answer on June 15, 2026 at 1:03 am

    You could make sure to only match the wanted number of hash signs by making sure that the first character of the heading text isn’t a hash sign. This can be done by using [^#] like this:

    string = re.sub('^#{1}([^#].*)$', '<h1>\\1</h1>', string, flags=re.MULTILINE)
    string = re.sub('^#{2}([^#].*)$', '<h2>\\1</h2>', string, flags=re.MULTILINE)
    

    This way the order of the rules won’t matter, making the rules more robust.

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