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Home/ Questions/Q 8950703
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T13:29:59+00:00 2026-06-15T13:29:59+00:00

I’m trying to make a next button for my database, so i can view

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I’m trying to make a “next button” for my database, so i can view one image at a time. However the way i have it right now only changes the url and not actually the image check it out here. It sticks to the image with the highest id on it (87) no matter what the url is. How do i fix this?

this is how my db looks

enter image description here

<?php 
require("includes/conn.php");

if (isset($_GET["imagecount"]))
$next = (int)$_GET["imagecount"]; //int is for sql injection 
else
    $next = 0;

$result = mysql_query("select * from people order by id desc limit $next, 1") or die(mysql_error());


?>



        <?php


            $result = mysql_query("select * from people order by id desc limit 0, 1 ") or die ("haznot DB: " . mysql_error());

            while ($row = mysql_fetch_assoc($result))
            {

                echo "<img src=\"images/" . $row['filename'] . "\" alt=\"\" /><br />";
            }

        ?>

<a href="images.php?imagecount=<?php echo $next+1; ?>">Next</a>     
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  1. Editorial Team
    Editorial Team
    2026-06-15T13:30:00+00:00Added an answer on June 15, 2026 at 1:30 pm

    You want WHERE id = $next in your query. Not what you have.

    Why do you have two mysql queries…

    "Select * FROM people WHERE `id` = $next"
    
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