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Home/ Questions/Q 1074265
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:06:05+00:00 2026-05-16T21:06:05+00:00

I’m trying to make a program that read a file line by line and

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I’m trying to make a program that read a file line by line and then put the readed line into a a linked list, my problem is to add the string to list. Look at the code, in the else test you can see my problem.

#include<stdlib.h>
#include<stdio.h>

struct list_el {
    char *ord;
       struct list_el * next;
};

typedef struct list_el item;

int main(int argc, char *argv[]) {
    int c;
    item *curr, *head;
    head = NULL;
    FILE *fileHandle = fopen("tresmaa.txt", "r");

    while((c = fgetc(fileHandle)) != '\n' || c != EOF)
        if(c == EOF) {
            printf("\n");
            break;
        } else {
            curr = (item*)malloc(sizeof(item));
            curr->ord = "I cant point curr -< ord = c, how can i point the readed sentences to the value Ord?";
            curr->next = head;
            head = curr;
            putchar(c);
        }
    curr = head;

   while(curr) {
      printf("%s\n", curr->ord);
      curr = curr->next ;
   }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:06:06+00:00Added an answer on May 16, 2026 at 9:06 pm
    curr->ord = "some string" is wrong
    

    instead you need to allocate a buffer and place the string in it

    e.g.

    curr->ord = malloc( strlen(yourstring) + 1 );
    strcpy(curr->ord, yourstring);
    

    because

    curr = (item*)malloc(sizeof(item));
    

    only allocates the struct including the ‘ord’ pointer, but not what it points to.

    another thing that looks a bit suspicious is

            curr->next = head;
            head = curr;
    

    looks more like the name should have been ‘prev’ and not ‘next’ the way you do it (LIFO)

    otherwise if you want a “normal” FIFO linked list just have a head ptr and an end ptr, then use the end ptr to append elements while keeping the head pointing to the first list element.

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