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Home/ Questions/Q 804497
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:55:48+00:00 2026-05-14T23:55:48+00:00

I’m trying to make a script to list all directories, subdirectories, and files in

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I’m trying to make a script to list all directories, subdirectories, and files in a given directory.

I tried this:

import sys, os

root = "/home/patate/directory/"
path = os.path.join(root, "targetdirectory")

for r, d, f in os.walk(path):
    for file in f:
        print(os.path.join(root, file))

Unfortunately, it doesn’t work properly. I get all the files, but not their complete paths.

For example, if the directory struct would be:

/home/patate/directory/targetdirectory/123/456/789/file.txt

It would print:

/home/patate/directory/targetdirectory/file.txt

I need the first result.

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  1. Editorial Team
    Editorial Team
    2026-05-14T23:55:49+00:00Added an answer on May 14, 2026 at 11:55 pm

    Use os.path.join to concatenate the directory and file name:

    import os
    
    for path, subdirs, files in os.walk(root):
        for name in files:
            print(os.path.join(path, name))
    

    Note the usage of path and not root in the concatenation, since using root would be incorrect.


    In Python 3.4, the pathlib module was added for easier path manipulations. So the equivalent to os.path.join would be:

    pathlib.PurePath(path, name)
    

    The advantage of pathlib is that you can use a variety of useful methods on paths. If you use the concrete Path variant you can also do actual OS calls through them, like changing into a directory, deleting the path, opening the file it points to and much more.

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