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Home/ Questions/Q 9221461
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T03:35:03+00:00 2026-06-18T03:35:03+00:00

I’m trying to make a sub in batch that find a string in a

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I’m trying to make a sub in batch that find a string in a string and replace it with a third one.
Searching around, I found here that I can erase a string with the SET command.

So, here’s what I tried:

:modifyString what with [in]
SET _what=%~1
ECHO "%_what%"
SET "_with=%~2
ECHO "%toWith%"
SET _In=%~3
ECHO "%_In%"
SET _In=%_In:%toWhat%=%toWith%%
ECHO %_In%
SET "%~3=%_In%"
EXIT /B

The ECHOs are there only for “debugging” purposes.

What I know is that the error is in…

SET _In=%_In:%toWhat%=%toWith%%

…because of the % character that close the %_in% variable.

I tried also things such as…

SET _In=%_In:!toWhat!=!toWith!%
SET _In=!_In:%toWhat%=%toWith%!

…and others without sense.

This is the main problem, the other is to return %_In% in [in].

Any tips?

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  1. Editorial Team
    Editorial Team
    2026-06-18T03:35:04+00:00Added an answer on June 18, 2026 at 3:35 am

    Here is an example using the ! DelayedExpansion method.

    @echo off
    setlocal EnableExtensions EnableDelayedExpansion
    set "xxString=All your base are belong to us"
    set "xxSubString=your base are belong"
    set "xxNewSubString=of your bases belong"
    echo Before
    set xx
    echo.
    set "xxString=!xxString:%xxSubString%=%xxNewSubString%!"
    echo After
    set xx
    endlocal
    pause >nul
    

    Output

    Before
    xxNewSubString=of your bases belong
    xxString=All your base are belong to us
    xxSubString=your base are belong
    
    After
    xxNewSubString=of your bases belong
    xxString=All of your bases belong to us
    xxSubString=your base are belong
    

    Fixed Yours

    @echo off
    :: Make sure that you have delayed expansion enabled.
    setlocal EnableDelayedExpansion
    
    :modifyString what with [in]
    SET "_what=%~1"
    SET "_with=%~2"
    SET "_In=%~3"
    ECHO "%_what%"
    ECHO "%_with%"
    ECHO "%_In%"
    :: The variable names were not the same as the ones
    :: defined above.
    SET _In=!_In:%_what%=%_with%!
    ECHO %_In%
    
    :: This will not change the value of the 3rd parameter
    :: but instead will create a new parameter with the
    :: value of %3 as the variable name.
    SET "%~3=%_In%"
    endlocal
    EXIT /B
    

    How to do the substring replacement without delayed expansion. Use the call command to create two levels of variable expansion. Use single % around variables to expand first and double %% around variables to expand second.

    @echo off
    setlocal EnableExtensions
    set "xxString=All your base are belong to us"
    set "xxSubString=your base are belong"
    set "xxNewSubString=of your bases belong"
    echo Before
    set xx
    echo.
    call set "xxString=%%xxString:%xxSubString%=%xxNewSubString%%%"
    echo After
    set xx
    endlocal
    pause >nul
    
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