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Home/ Questions/Q 6669867
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:12:06+00:00 2026-05-26T03:12:06+00:00

I’m trying to make a Vector3D class in my c++ application. For my entire

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I’m trying to make a Vector3D class in my c++ application. For my entire program, I’m using a namespace. In this namespace I’ve declared my Vector3D class and an overloaded operator<< for it as such:

namespace space
{
    class Vector3D
    {
      public:
        float x, y, z;

        Vector3D(float _x = 0, float _y = 0, float _z = 0);
        Vector3D(const Vector3D & _vector);

        Vector3D & operator=(const Vector3D & _vector);
        Vector3D operator*(float _scalar);
        Vector3D operator*(const Vector3D & _vector); //CROSS PRODUCT

        float magnitude() const;
        float magnitude2() const; //FOR SPEED
        Vector3D normalize() const;
    };

    std::ostream & operator<<(std::ostream &, const Vector3D &);
}

It compiles just fine too. My problem is to cout a Vector3D, I have to manually call

space::operator<<(cout, vector);

which is a pain. I’d like to try to avoid “using namespace space;”, because I like the prefix on all the rest of the objects in “namespace space”.

My final question: Is there any way to call an overloaded operator function inside a namespace without using that namespace?

Thanks for the help.

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:12:06+00:00Added an answer on May 26, 2026 at 3:12 am

    My problem is to cout a Vector3D, I have to manually call space::operator<<(cout, vector);

    You don’t, that’s what ADL (Argument-dependent name lookup, also known as Koenig’s lookup) is about. It should be enough to do

    cout << vector;
    

    If it doesn’t work, either you are working with an ancient compiler or you are doing something else wrong.

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