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Home/ Questions/Q 6361883
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:50:05+00:00 2026-05-24T23:50:05+00:00

I’m trying to make an ajax call from jquery to a rest service. The

  • 0

I’m trying to make an ajax call from jquery to a rest service. The rest service used is right from a tutorial of mkyong’s blog, this one: http://www.mkyong.com/webservices/jax-rs/integrate-jackson-with-resteasy/

The service works, but when i try to make a call from jQuery, in Firebug there is a 200 status code, but in the response section, nothing.

Here is the html page with the ajax call:

<html>
<head>
    <script type="text/javascript" src="jquery-1.6.2.min.js"></script>
</head>

<body>  

<button id="ajax">ajax call</button>
<button id="json">json</button>

<script type="text/javascript">
    $('#json').click(function(){ 
        alert('json');
         $.getJSON("http://localhost:8080/restws/json/product/get",
         function(data) {
            alert(data);         
          });   
    });

    $('#ajax').click(function(){ 
        alert('ajax');
         $.ajax({ 
             type: "GET",
             dataType: "json",
             url: "http://localhost:8080/restws/json/product/get",
             success: function(data){        
                alert(data);
             }
         });
    });

</script>



</body>

</html>

I can’t figure it out where I went wrong, could you please tell me what i am doing wrong?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:50:06+00:00Added an answer on May 24, 2026 at 11:50 pm

    You are running your HTML from a different host than the host you are requesting. Because of this, you are getting blocked by the same origin policy.

    One way around this is to use JSONP. This allows cross-site requests.

    In JSON, you are returned:

    {a: 5, b: 6}
    

    In JSONP, the JSON is wrapped in a function call, so it becomes a script, and not an object.

    callback({a: 5, b: 6})
    

    You need to edit your REST service to accept a parameter called callback, and then to use the value of that parameter as the function name. You should also change the content-type to application/javascript.

    For example: http://localhost:8080/restws/json/product/get?callback=process should output:

    process({a: 5, b: 6})
    

    In your JavaScript, you will need to tell jQuery to use JSONP. To do this, you need to append ?callback=? to the URL.

    $.getJSON("http://localhost:8080/restws/json/product/get?callback=?",
       function(data) {
         alert(data);         
       });
    

    If you use $.ajax, it will auto append the ?callback=? if you tell it to use jsonp.

    $.ajax({ 
       type: "GET",
       dataType: "jsonp",
       url: "http://localhost:8080/restws/json/product/get",
       success: function(data){        
         alert(data);
       }
    });
    
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