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Home/ Questions/Q 8867497
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T17:02:59+00:00 2026-06-14T17:02:59+00:00

I’m trying to make array of strings, I have function rLine which reads line

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I’m trying to make array of strings, I have function rLine which reads line from stdin, each inputted line I need to save in array, but I don’t have any idea about number of inputted string lines. So I need to dynamically increase array size to store them, I wrote such code:

char *res[2], *old = res;
while( 1 ){
  line = rLine( stdin ), len = strlen( line );
  res[row] = (char*)malloc( len + 1);
  strcpy( res[row++], line);
  res = (char**) realloc( res, row ); /* adding 1 more row, not sure adding size row? */
  if ( /*some cond*/ ) break;
}

But this code doesn’t seem to work, how correctly declare array and increase it size?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T17:03:00+00:00Added an answer on June 14, 2026 at 5:03 pm

    As I said in the comment, an array of pointers is different than a pointer to pointer. You can’t try to assign allocated memory to an array.

    You should declare res as a pointer to pointer and allocate memory at the beginning of the loop before using it.

    Try it out like this:

    char **res = NULL, *old = res;
    while( 1 ){
      line = rLine( stdin ), len = strlen( line );
      res = (char**) realloc( res, sizeof(char**) * (row + 1) ); /* adding 1 more row, not sure adding size row? */
      res[row] = (char*)malloc( len + 1);
      strcpy( res[row++], line);
      if ( /*some cond*/ ) break;
    }
    

    Remember that arrays decay to pointers in most situations but are handled very differently underneath.

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