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Home/ Questions/Q 8613419
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T04:52:15+00:00 2026-06-12T04:52:15+00:00

I’m trying to make Erlang program that finds prime numbers with processes (ineffective, I

  • 0

I’m trying to make Erlang program that finds prime numbers with processes (ineffective, I know, but hey, it’s just for fun 🙂 ) – something along the lines of numbersimulation.com.

On each “tick” the server spawns new process (“number”) that increments its counter. If counter == that number, it’s a factor, so we let server know. If server doesn’t get any messages, it’s a prime number.

On small numbers (primes upto N, the server(50,L) line) it’s okay, but on the bigger ones it crashes with:

Error in process <0.46.0> with exit value: {badarg,[{primes,number,2,[{file,"primes.erl"},{line,31}]}]}

The line 31 is the server ! hit one – but I don’t understand why it fails. Maybe the line that fails is the one after, number(N,1) ? But why would that fail?

The code:

-module(primes).
-compile(export_all).

main() ->
  pg:create(numbers),
  Server_PID = spawn(?MODULE,server,[]),
  register(server,Server_PID),
  ok.

server()     -> server(2,[]).
server(50,L) -> io:format("Primes: ~p~n",[L]);
server(N,L)  ->
  Num_PID = spawn(?MODULE,number,[N]),
  pg:join(numbers,Num_PID),
  pg:send(numbers,tick),
  receive
    hit ->
      flush(),
      server(N+1,L)
  after 100 ->
      server(N+1,[N|L])
  end.

number(N)   -> receive {pg_message,_,_,tick} -> number(N,1) end.
number(N,I) ->
  receive
    {pg_message,_,_,tick} ->
      if
        N =:= I ->
          server ! hit,
          number(N,1);
        true ->
          number(N,I+1)
      end
  end.

flush() ->
  receive _ -> flush()
  after   0 -> ok end.
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  1. Editorial Team
    Editorial Team
    2026-06-12T04:52:17+00:00Added an answer on June 12, 2026 at 4:52 am

    When a registered process dies the name it was registered under is no longer registered. While sending a message to a pid which refers to a dead process is perfectly legal (the message just disappears) sending to an unregistered name is an error, even if the name was once registered.

    In your code the server process does 50 loops spawning a new process and waiting for a hit message or timeout. After that the server/2 function ends and the server process dies. When it dies the name server is no longer registered so trying to send a message to it generates a badarg error.

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