Question

I’m trying to make every second TD in my TABLE (html) another color, and therefore I am using this variable:

$bgColor = ($bgColor == "#eee") ? "#fff" : "#eee";

And then I’m calling it in my table:

<td style='background:<?=$bgColor;?>'></td>

But then I get an error: Undefined variable with the $bgColor = ($bgColor etc.);

It’s working, but I get that error.

How would I fix this? Normally I’ve get this error when I’ve forgot an if(isset()); but thats not the situation here.

Thanks in forward 🙂

Answer 1

$bgColor = (isset($bgColor) && $bgColor == "#eee") ? "#fff" : "#eee";