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Home/ Questions/Q 9243241
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T08:46:01+00:00 2026-06-18T08:46:01+00:00

I’m trying to map the following inheritance in EntityFramework Code First public class Member

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I’m trying to map the following inheritance in EntityFramework Code First

public class Member
{
    public string ProjectName { get; set; }
    public string AssemblyName { get; set; }
    public string NamespaceName { get; set; }
    public string TypeName { get; set; }
    public string Signature { get; set; }
    public string DisplayName { get; set; }
    public MemberType Type { get; set; }
    public string Summary { get; set; }
    public bool IsStatic { get; set; }
    public bool IsInherited { get; set; }

    //public virtual Type ParentType { get; set; } // ignore this
}

public class Field : Member
{
    public string ValueType { get; set; }
    public bool IsReadOnly { get; set; }
    public bool IsVolatile { get; set; }
}

public enum MemberType
{
    Constructor,
    Field,
    Method,
    Operator,
    Property
}

As you can probably guess from the code, in time I plan to add more subclasses of Member (named Constructor, Method, Operator and Property), but first I’d just like to get the Field one to work properly.

My mapping-code looks like this

modelBuilder.Entities<Member>().Configure(config =>
{
    config.HasKey(m => new { m.ProjectName, m.AssemblyName, m.NamespaceName, m.TypeName, m.Signature });
    config.Property(m => m.DisplayName).IsRequired();
    config.ToTable("Members");
});

modelBuilder.Entities<Field>().Configure(config =>
{
    config.HasKey(f => new { f.ProjectName, f.AssemblyName, f.NamespaceName, f.TypeName, f.Signature });
});

modelBuilder.Entity<Member>()
    .Map<Field>(m => 
    {
        m.ToTable("Fields");
        m.Requires("Type").HasValue((int)Service.DataTypes.MemberType.Field).IsRequired();
    }); // note: realy not certain about this one

What I would like, is to generate two tables. One named “Members”, and one named “Fields”, and use the Type-property in the Member-class as a discriminator, and I’m sure I’m just doing something really stupid here, but I cannot for the life of me figure out how to do it. Because with the current code, it generates a column in the “Fields” table named “Type”, which you obviously wouldn’t need as that’d be a constant.

So I’m just wondering, could somebody please tell me what on earth I’m doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T08:46:03+00:00Added an answer on June 18, 2026 at 8:46 am

    Is there a typo there ? Your Class has a field Valuetype Not Type.

    I have never tried with with JUST 1 mapping, try with a second table to make sure.

    modelBuilder.Entity<Member>()
    .Map<Field>(m => 
    {
        m.ToTable("Fields");
        m.Requires("ValueType").HasValue((int)Service.DataTypes.MemberType.Field).IsRequired();
    })
    .Map<SECONDTYPE>(m =>
    {
        m.Requires("ValueType").HasValue(42);
    }); 
    
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