Question

I’m trying to open a folder from a distant server. I wrote :

if ($folderHandle = opendir($folder))

where $folder = "ftp://xxx:[e-mail]:21"

I get the weird error Warning: opendir(ftp://...:21): failed to open dir: operation failed in ... on line 38

Any ideas as to where I should go from here ? Is it a problem with the FTP credentials ?

Answer 1

You could use PHP’s FTP Capabilities to remotely connect to the server and get a directory listing:

// set up basic connection
$conn_id = ftp_connect('otherserver.example.com'); 

// login with username and password
$login_result = ftp_login($conn_id, 'username', 'password'); 

// check connection
if ((!$conn_id) || (!$login_result)) { 
    echo "FTP connection has failed!";
    exit; 
}

// upload the file
$upload = ftp_put($conn_id, $destination_file, $source_file, FTP_BINARY); 

// check upload status
if (!$upload) { 
    echo "FTP upload has failed!";
} else {
    echo "Uploaded $source_file to $ftp_server as $destination_file";
}

// Retrieve directory listing
$files = ftp_nlist($conn_id, '/remote_dir');

// close the FTP stream 
ftp_close($conn_id);