Question

I’m trying to parse a json result from the next google Query:

http://www.google.com/ig/calculator?hl=en&q=1USD=?MXN

The result is this:

{lhs: "1 U.S. dollar",rhs: "13.3317335 Mexican pesos",error: "",icc: true}

So i’m just trying to decode with this:

import json, urllib2

j=urllib2.urlopen("http://www.google.com/ig/calculator?hl=en&q=1USD=?MXN")
print json.load(j)

But i’m having this error (Traceback):

Traceback (most recent call last):
  File "/home/rafael/gitSources/PythonConcept/Monpy/negApi.py", line 4, in <module>
    print json.load(j)
  File "/usr/lib/python2.7/json/__init__.py", line 278, in load
    **kw)
  File "/usr/lib/python2.7/json/__init__.py", line 326, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib/python2.7/json/decoder.py", line 382, in raw_decode
    obj, end = self.scan_once(s, idx)
ValueError: Expecting property name: line 1 column 1 (char 1)
[Finished in 0.6s with exit code 1]

I don’t know what i’m doing wrong, I just read many tutorials :/

Thanks :)!

Answer 1

This is not JSON but you can still parse it yourself – like this:

import ast

resp = '{lhs: "1 U.S. dollar",rhs: "13.3317335 Mexican pesos",error: "",icc: true}'

d = {}
for pair in resp[1:-1].split(','):
    (k,v) = pair.split(':')
    v = v.strip()
    if v == "true":
        v = "True"
    try:
        v = ast.literal_eval(v)
    except:
        print "Couldn't eval " + v
    d[k] = v

print d

You could also fix up the formatting to be json and then use the json parser like this:

import json

resp = '{lhs: "1 U.S. dollar",rhs: "13.3317335 Mexican pesos",error: "",icc: true}'

s = "{"    
for pair in resp[1:-1].split(','):
    (k,v) = pair.split(':')
    s += '"%s" : %s,' % (k,v)
s = s[:-1] + "}"

print json.loads(s)