Question

I’m trying to parse a simple string to an array of *char and for some reason when I use string.c_str() it puts the entire string into *char[0] and the rest of the array is left blank (I originally thought that chars could only hold one ASCII character but I guess that they act differently as pointers), could anyone have a scan through my function and tell me if there are any obvious mistakes?

static void SetGame()
{
    // Variable Initiation
    int myRandom = rand() % (numOfWords - 1);
    lengthOfString = wordArray[myRandom].length();

    // Reinitiate Pointer Arrays
    stringArray = new string[lengthOfString];
    isDiscoveredArray = new bool[lengthOfString];

    // Parse string to the array of characters
    *stringArray = wordArray[myRandom].c_str();

    // Set each boolean array value to false
    for (int i = 0; i < sizeof(isDiscoveredArray); i++)
    {
        isDiscoveredArray[i] = false;
    }
}

Here are my decelerations of the pointers

// Global Variable and pointer Declerations
string *wordArray;
int numOfWords;
string *stringArray;
int lengthOfString;
bool *isDiscoveredArray;

Any ideas? Thanks.

Answer 1

You are mixing types here. First you build an array of strings and store it in a pointer, then you assign to the first element a const char* coming from c_str. The code you currently have would be if your were creating a string for every character in your selected word.

Make your “stringArray” a const char* to fit with the code you already have, but remove the memory allocation.