Question

I’m trying to parse an OpenOffice spreadsheet to obtain rows with unique values in the first column.

I.E., I would like to retrieve from the following XML fragment all <table:table-row> elements with unique <text:p> values in the first child <table:table-cell>.

    <table:table table:name="foo">
        <table:table-row>
            <table:table-cell>
                <text:p>1</text:p>
            </table:table-cell>
            <table:table-cell>
                <text:p>foo</text:p>
            </table:table-cell>
        </table:table-row>
        <table:table-row>
            <table:table-cell>
                <text:p>2</text:p>
            </table:table-cell>
            <table:table-cell>
                <text:p>bar</text:p>
            </table:table-cell>
        </table:table-row>
        <table:table-row>
            <table:table-cell>
                <text:p>1</text:p>
            </table:table-cell>
            <table:table-cell>
                <text:p>baz</text:p>
            </table:table-cell>
        </table:table-row>
    </table:table>

I’ll like to get the below output as Nodes

        <table:table-row>
            <table:table-cell>
                <text:p>1</text:p>
            </table:table-cell>
            <table:table-cell>
                <text:p>foo</text:p>
            </table:table-cell>
        </table:table-row>
        <table:table-row>
            <table:table-cell>
                <text:p>2</text:p>
            </table:table-cell>
            <table:table-cell>
                <text:p>bar</text:p>
            </table:table-cell>
        </table:table-row>

How can I do this with XPath?

Answer 1

This XPath produces desired output:
/table:table/table:table-row[not(./table:table-cell[1]/text:p/text() = preceding-sibling::table:table-row/table:table-cell[1]/text:p/text())]