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Home/ Questions/Q 392125
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:07:42+00:00 2026-05-12T16:07:42+00:00

I’m trying to pass a parameter to an XSLT stylesheet, but all i’m getting

  • 0

I’m trying to pass a parameter to an XSLT stylesheet, but all i’m getting is an empty xml document when the document is transformed using XSlCompiledTransform.

This is the C# method used to add the parameters(after adding in people’s suggestions)

private static void CreateHierarchy(string manID)
    {

        string man_ID = manID;

        XsltArgumentList argsList = new XsltArgumentList();
        argsList.AddParam("Boss_ID","",man_ID);

        XslCompiledTransform transform = new XslCompiledTransform();
        transform.Load("htransform.xslt");

        using (StreamWriter sw = new StreamWriter("output.xml"))
        {
            transform.Transform("LU AIB.xml", argsList, sw);
        } 


    }

and here is the stylesheet. The parameter i’m passing in is ‘Boss_ID’

   <?xml version="1.0" encoding="utf-8"?>
   <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <xsl:output method="xml" indent="yes" />
   <xsl:template match="OrgDoc">
     <xsl:param name="Boss_ID"></xsl:param>
    <xsl:processing-instruction name="xml-stylesheet">
    <xsl:text>type="text/xsl" href="..\styles\orgcharts.xsl" </xsl:text>
  </xsl:processing-instruction>
    <OrgDoc>
      <xsl:for-each select="PosDets[@OC_Man = $Boss_ID]">
      <PosDets OC_Pos="{@OC_Pos}" OC_Sub="{@OC_Sub}" OC_Man="{@OC_Man}" OC_Ttl="{@OC_Ttl}" OC_Rnk="{@OC_Rnk}" OC_Bdg="{@OC_Bdg}" OC_Fnd="{@OC_Fnd}"   OC_OL3="{@OC_OL3}"    OC_Tmp="{@OC_Tmp}">
          <xsl:apply-templates select="../PosDets">
            <xsl:with-param name="mgrid" select="@OC_Pos"/>
          </xsl:apply-templates>
        </PosDets>  
      </xsl:for-each>
    </OrgDoc>
  </xsl:template>
  <xsl:template match="PosDets" > 
    <xsl:param name="mgrid" />
    <xsl:if test="@OC_Man=$mgrid" >
      <PosDets OC_Pos="{@OC_Pos}" OC_Sub="{@OC_Sub}" OC_Man="{@OC_Man}" OC_Ttl="{@OC_Ttl}" OC_Rnk="{@OC_Rnk}" OC_Bdg="{@OC_Bdg}" OC_Fnd="{@OC_Fnd}"   OC_OL3="{@OC_OL3}"    OC_Tmp="{@OC_Tmp}">
        <xsl:apply-templates select="../PosDets">
          <xsl:with-param name="mgrid" select="@OC_Pos"/>
        </xsl:apply-templates>
      </PosDets>  
    </xsl:if>
  </xsl:template>


   </xsl:stylesheet>  

I can’t post all of the input document as it’s confidential info, but here’s a brief sanitised version

<OrgDoc><PosDets OC_Pos="161" OC_Man="9" OC_Ttl="Boss" OC_Rank="" OC_OL3="LU AIB" OC_Bdg="Has Budget" OC_Fnd="Payroll" OC_Sub="" OC_Tmp="" /><PosDets OC_Pos="190" OC_Man="161" OC_Ttl="Boss" OC_Rank="" OC_OL3="LU AIB" OC_Bdg="Has Budget" OC_Fnd="Payroll" OC_Sub="" OC_Tmp="" /><PosDets OC_Pos="199" OC_Man="190" OC_Ttl="Boss" OC_Rank="" OC_OL3="LU AIB" OC_Bdg="Has Budget" OC_Fnd="Payroll" OC_Sub="" OC_Tmp="" /></OrgDoc>

Can anyone help?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:07:42+00:00Added an answer on May 12, 2026 at 4:07 pm

    You need to define the parameter within your XSLT and you also need to pass the XsltArgumentList as an argument to the Transform call:

    private static void CreateHierarchy(string manID)
    {
        string man_ID = manID;
    
        XsltArgumentList argsList = new XsltArgumentList();
        argsList.AddParam("Boss_ID", "", man_ID);
    
        XslCompiledTransform transform = new XslCompiledTransform(true);
        transform.Load("htransform.xslt");
    
        using (StreamWriter sw = new StreamWriter("output.xml"))
        {
            transform.Transform("LU AIB.xml", argsList, sw);
        }
    }
    

    Please note that the xsl:param must be defined below the xsl:stylesheet element:

    <?xml version="1.0" encoding="utf-8"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
      <xsl:output method="xml" indent="yes" />
    
      <xsl:param name="Boss_ID"></xsl:param>
    
      <xsl:template match="OrgDoc">
    
         <!-- template body goes here -->
    
      </xsl:template>
    
    
    </xsl:stylesheet>
    

    This simple XSLT sample will create just a small output document containing one XML node with its contents set to the value of your parameter. Have a try:

    <?xml version="1.0" encoding="utf-8"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
      <xsl:output method="xml" indent="yes" />
      <xsl:param name="Boss_ID"></xsl:param>
    
      <xsl:template match="/">
        <out>
          <xsl:value-of select="$Boss_ID" />
        </out>
      </xsl:template>
    
    </xsl:stylesheet>
    
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