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Home/ Questions/Q 7959027
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:30:33+00:00 2026-06-04T04:30:33+00:00

I’m trying to pass some variables using jquery and ajax but for some reason

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I’m trying to pass some variables using jquery and ajax but for some reason its not working. Here is the code.

<div id=' . $result['game_id'] . ' name="' . $user_id . '"  class="rate_widget" >
            <div class="star_1 ratings_stars"></div>
            <div class="star_2 ratings_stars"></div>
            <div class="star_3 ratings_stars"></div>
            <div class="star_4 ratings_stars"></div>
            <div class="star_5 ratings_stars"></div>
            <div class="total_votes">vote data</div>
        </div>

when i check chrome’s developer tools i can see that the id and name attributes are set correctly .

Here is the javascript(using jquery) i put an alert box to see if the value was set but i get undefined. Just started learning ajax and jquery this week any help would be appreciated.

$('.rate_widget').each(function() {
        var widget = this;
        var out_data = {
            game_id : $(widget).attr('id'),
            user_id : $(widget).attr('name')
        };
        alert(game_id);
        $.post(
            'ratings.php',
            out_data,
            function(INFO) {
                $(widget).data( 'fsr', INFO );
                set_votes(widget);
            },
            'json'
        );

In case its not clear im trying to send game_id and user_id with the corresponding values to a php script but im getting the error. Also i know there is another question with the same name but i checked it and it didn’t help.

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  1. Editorial Team
    Editorial Team
    2026-06-04T04:30:33+00:00Added an answer on June 4, 2026 at 4:30 am

    You can’t reference game_id like that. game_id is an index in the out_data object.

    To alert the correct value you’d have to use :

    alert(out_data['game_id']);
    

    I’d also recommend wrapping your object indexes with quotes – just to make it a little more readable –

    var out_data = {
      'game_id' : $(widget).attr('id'),
      'user_id' : $(widget).attr('name')
    };
    
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