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Home/ Questions/Q 9266747
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T14:23:23+00:00 2026-06-18T14:23:23+00:00

I’m trying to play with MethodHandles in Java 7. I have a class here:

  • 0

I’m trying to play with MethodHandles in Java 7.

I have a class here:

public class TestCase {
    MethodType mt;

    public static void main(String args[])
    {
        Android a = new Android();
        MethodHandleExample.doSomething(a);
    }
}

class Android {
    public void thisIsMagic()
    {
        System.out.println("Might be called from the method handel");
    }
}

And the method handle example calls are here in this class:

public class MethodHandleExample {

    public static void doSomething(Object obj)
    {
        MethodHandle methodHandle = null ;
        MethodType mt = MethodType.methodType(void.class);
        MethodHandles.Lookup lookup = MethodHandles.lookup();

        try{
            try {
                methodHandle = lookup.findVirtual(obj.getClass(),"thisIsMagic",mt);
            } catch (NoSuchMethodException e) {
                e.printStackTrace();  //To change body of catch statement use File | Settings | File Templates.
            } catch (IllegalAccessException e) {
                e.printStackTrace();  //To change body of catch statement use File | Settings | File Templates.
            }
        }
        finally {

        }
        try {
            methodHandle.invoke();
        } catch (Throwable throwable) {
            throwable.printStackTrace();  //To change body of catch statement use File | Settings | File Templates.
        }
    }
}

but when I try to run this code I get an exception like this:

java.lang.invoke.WrongMethodTypeException: cannot convert MethodHandle(Android)void to ()void
    at java.lang.invoke.MethodHandle.asType(MethodHandle.java:691)
    at java.lang.invoke.InvokeGeneric.dispatch(InvokeGeneric.java:103)
    at com.generic.exception.AnnotationParser.doSomething(AnnotationParser.java:35)
    at com.generic.exception.TestCase.main(TestCase.java:18)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:601)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)

The exception I’m getting is on the line :

 methodHandle.invoke();

Not sure how do I invoke the underlying method in this case.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T14:23:24+00:00Added an answer on June 18, 2026 at 2:23 pm

    Add:

    methodHandle.invoke(obj)
    

    You must give an object to run the method on.

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