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Home/ Questions/Q 7952893
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T02:59:55+00:00 2026-06-04T02:59:55+00:00

I’m trying to plot some cities on Google’s Geochart. This function works perfectly fine

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I’m trying to plot some cities on Google’s Geochart. This function works perfectly fine and will plot cities.

function drawMarkersMap() {
  var newInfo = google.visualization.arrayToDataTable([
   ['City'],
   ['San Diego'],
   ['Los Angeles'],
   ['San Jose']
  ]);

While that’s nice and all, I’m generating my cities from my database via php. So, let’s just say we have this php array

<?php $city = array("San Diego", "Los Angeles", "San Jose"); ?>

Now here comes the part where I’m struggling. I can’t seem to get a loop working properly so that I can output each city separately.

When I do this only the first city in the array(San Diego) will display and I understand why…I’m just showing that this method will at least print “something”

function drawMarkersMap() {
  var newInfo = google.visualization.arrayToDataTable([
    ['City'],
    ['<?php foreach($city as $location){ echo json_encode($location); } ?>']
]);
//options here
}

So, I’m attempting to loop through and print each item in the array using javascript but I don’t seem to have the logic correct

function drawMarkersMap() {
  var newInfo = google.visualization.arrayToDataTable([
    ['City'],
    for(i=0;i<json_encode($city).count;i++){
     //some kind of print statement mixing php and javascript. I need help here please!
     }
]);

Here’s the entire page

<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Google Visualization API Sample</title>
<script type="text/javascript" src="http://www.google.com/jsapi"></script>

<?
$city = array("San Jose","Los Angeles","San Diego");
foreach($city as $key=>$value) {
     echo "$value";
}  
?>
<script type="text/javascript">
 google.load('visualization', '1.1', {packages: ['geochart']});


function drawMarkersMap() {
  var newInfo = google.visualization.arrayToDataTable([
    ['City'],
['<?php echo json_encode($city);  ?>']
]);

var chart = new google.visualization.GeoChart(document.getElementById('chart_div'));

chart.draw(newInfo, {width: 556, height: 347, displayMode: 'markers', region: 'US-CA', resolution: 'provinces'});
}


google.setOnLoadCallback(drawMarkersMap);
</script>
</head>
<body style="font-family: Arial;border: 0 none;">
<div id="chart_div"></div>
</body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T02:59:57+00:00Added an answer on June 4, 2026 at 2:59 am
    <?php $city = array(array('City'), array('San Diego'), array('Los Angeles'), array('San Jose')); ?>
    
    var newInfo = google.visualization.arrayToDataTable(<?php echo json_encode($city); ?>);
    

    This recreates exactly the same array structure as your original script.

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