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Home/ Questions/Q 6219523
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:47:54+00:00 2026-05-24T07:47:54+00:00

I’m trying to plot the batman equation. A solution in sympy or matplotlib will

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I’m trying to plot the batman equation. A solution in sympy or matplotlib will be great (sage isn’t cool because I’m using windows). The problem is that if I comment out certain parts the part of the figure appears but with all the F *= parts, I get a blank plot.

import matplotlib.pyplot
from numpy import arange
from numpy import meshgrid
from numpy import sqrt
from numpy import real

delta = 0.01
xrange = arange(-7.0, 7.0, delta)
yrange = arange(-3.0, 3.0, delta)
x, y = meshgrid(xrange,yrange)

F = 1
F *= (((x/7) ** 2) * sqrt(abs(abs(x) - 3)/(abs(x) - 3)) + ((y / 3) ** 2) * sqrt(abs(y + (3 * sqrt(33)) / 7)/(y + (3 * sqrt(33)) / 7)) - 1)
F *= (abs(x/2) - ((3 * sqrt(33) - 7)/112) * x**2 - 3 + sqrt(1 - (abs(abs(x) - 2) - 1) ** 2 ) - y)
F *= (9 * sqrt(abs((abs(x) - 1) * (abs(x) - 3/4))/((1 - abs(x)) * (abs(x) - 3/4))) - 8 * abs(x) - y)
F *= (3 * abs(x) + 0.75 * sqrt(abs((abs(x) - 3/4) * (abs(x) - 1/2))/((3/4 - abs(x)) * (abs(x) - 1/2))) - y)
F *= ((9/4) * sqrt(abs((x - 1/2) * (x + 1/2))/((1/2 - x) * (1/2 + x))) - y)
F *= ((6 * sqrt(10)) / 7 + (3/2 - abs(x)/2) * sqrt(abs(abs(x) - 1)/(abs(x) - 1)) - ((6 * sqrt(10))/ 14) * sqrt(4 - (abs(x) - 1) ** 2 ) - y)
G = 0

matplotlib.pyplot.contour(x, y, (F - G), [0])
matplotlib.pyplot.show()

What’s going on here? If the graph is zero for one multiplicand, it should still be so no matter which other multiplicands I throw in there.

source of the batman equation: http://www.reddit.com/r/pics/comments/j2qjc/do_you_like_batman_do_you_like_math_my_math/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:47:55+00:00Added an answer on May 24, 2026 at 7:47 am

    The parameter of sqrt is negative for many points, so the finally products are all NaN. You can plot every factor as following:

    from __future__ import division  # this is important, otherwise 1/2 will be 0
    import matplotlib.pyplot
    from numpy import arange
    from numpy import meshgrid
    from numpy import sqrt
    from numpy import real
    
    
    delta = 0.01
    xrange = arange(-7.0, 7.0, delta)
    yrange = arange(-3.0, 3.0, delta)
    x, y = meshgrid(xrange,yrange)
    
    F1 = (((x/7) ** 2) * sqrt(abs(abs(x) - 3)/(abs(x) - 3)) + ((y / 3) ** 2) * sqrt(abs(y + (3 * sqrt(33)) / 7)/(y + (3 * sqrt(33)) / 7)) - 1)
    F2 = (abs(x/2) - ((3 * sqrt(33) - 7)/112) * x**2 - 3 + sqrt(1 - (abs(abs(x) - 2) - 1) ** 2 ) - y)
    F3 = (9 * sqrt(abs((abs(x) - 1) * (abs(x) - 3/4))/((1 - abs(x)) * (abs(x) - 3/4))) - 8 * abs(x) - y)
    F4 = (3 * abs(x) + 0.75 * sqrt(abs((abs(x) - 3/4) * (abs(x) - 1/2))/((3/4 - abs(x)) * (abs(x) - 1/2))) - y)
    F5 = ((9/4) * sqrt(abs((x - 1/2) * (x + 1/2))/((1/2 - x) * (1/2 + x))) - y)
    F6 = ((6 * sqrt(10)) / 7 + (3/2 - abs(x)/2) * sqrt(abs(abs(x) - 1)/(abs(x) - 1)) - ((6 * sqrt(10))/ 14) * sqrt(4 - (abs(x) - 1) ** 2 ) - y)
    
    
    for f in [F1,F2,F3,F4,F5,F6]:
        matplotlib.pyplot.contour(x, y, f, [0])
    matplotlib.pyplot.show()
    

    the result plot:
    enter image description here

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