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Home/ Questions/Q 9075687
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T18:55:10+00:00 2026-06-16T18:55:10+00:00

I’m trying to populate a list view from a SQLite db I can create

  • 0

I’m trying to populate a list view from a SQLite db I can create the db and add items to it and display them in a TextView but for some reason not on a ListView

Is it that sData is the wrong type of object?

Can anyone help, please?

public void DBTest() {

        SQLiteDatabase myDB = null;
        String TableName = "myTable";

        /* Create a Database. */
        try {
            myDB = this.openOrCreateDatabase(DATABASE_NAME, MODE_PRIVATE, null);

            /* Create a Table in the Database. */
            myDB.execSQL("CREATE TABLE IF NOT EXISTS "
                    + TableName
                    + " (_id integer primary key autoincrement, name text, script text, su short);");

            /* Insert data to a Table*/
            myDB.execSQL("INSERT INTO "
                    + TableName
                    + " (name, script, su)"
                    + " VALUES ('hello', 'reboot', 1);");

            /*retrieve data from database */
            Cursor c = myDB.rawQuery("SELECT * FROM " + TableName, null);

            int Column1 = c.getColumnIndex("name");
            int Column2 = c.getColumnIndex("script");
            int Column3 = c.getColumnIndex("su");

            // Check if our result was valid.
            c.moveToFirst();
            String sData="";
            if (c != null) {
                // Loop through all Results
                do {
                    String Name = c.getString(Column1);
                    String Script = c.getString(Column2);
                    int su = c.getInt(Column3);
                    sData = sData + Name + " " + Script + " " + su + "\n";
                } while (c.moveToNext());
            }

            ListView lv = (ListView) findViewById(R.id.mainListView);
            lv.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_single_choice, sData));

        } catch (Exception e) {
            Log.e("Error", "Error", e);
        } finally {
            if (myDB != null)
                myDB.close();
        }
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T18:55:11+00:00Added an answer on June 16, 2026 at 6:55 pm

    You will end up with a ListView with just one single item, the value of sData. You need to create a list such as:

    c.moveToFirst();
    ArrayList<String> sData = new ArrayList<String>();
    if (c != null) {
        do {
            String Name = c.getString(Column1);
            String Script = c.getString(Column2);
            int su = c.getInt(Column3);
            sData.add(Name + " " + Script + " " + su);
        } while (c.moveToNext());
    }
    
    ListView lv = (ListView) findViewById(R.id.mainListView);
    lv.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_single_choice, sData));
    

    I also recommend you change your cursor looping to be similar to this:

    // cursor left as it came from the database because it starts at the row before the first row
    ArrayList<String> sData = new ArrayList<String>();
    while (c.moveToNext()) {
        String Name = c.getString(Column1);
        String Script = c.getString(Column2);
        int su = c.getInt(Column3);
        sData.add(Name + " " + Script + " " + su);
    }
    

    because at the moment you are not checking the return value of moveToFirst, and it may return false (meaning there are no rows), however your do-while loop means the cursor will be read at least once whether or not it has 0 rows, and if there are 0 rows, you app will crash.

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