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Home/ Questions/Q 8973811
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T18:32:12+00:00 2026-06-15T18:32:12+00:00

I’m trying to program a Login-System for Android (in Eclipse) and have to get

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I’m trying to program a Login-System for Android (in Eclipse) and have to get the data from an external MySQL-DB.

Source I took the code for it: Connecting to MySQL Database

The Website I’m trying to fetch the data from is here.(I know there are some safety issues, blabla, this is not my problem right now^^)

The Problem I have, is when I try to run the Application, The Error “No Password found”.
This Error is catched within this Code:

ArrayList<String> passwort = new ArrayList<String>();
ArrayList<String> benutzer = new ArrayList<String>();
try{
  jArray = new JSONArray(result);
  JSONObject json_data=null;
  for(int i=0;i<jArray.length();i++){
         json_data = jArray.getJSONObject(i);
         passwort.add(json_data.getString("pw"));
         benutzer.add(json_data.getString("benutzer"));

     }
  Intent intent = new Intent(this, MainActivity.class);
  intent.putExtra("arrayBenutzerExtra", benutzer);
  intent.putExtra("arrayPasswortExtra", passwort);
  startActivity(intent);

    }
    catch(JSONException e1){
      Toast.makeText(getBaseContext(), "No Password found" ,Toast.LENGTH_LONG).show();
    } catch (ParseException e1) {
        e1.printStackTrace();
}

As addition, here is the code where I connect with the website, but it doesn’t seem to be the problem, though I don’t get an error message about that!

try{
 HttpClient httpclient = new DefaultHttpClient();
 HttpPost httppost = new HttpPost("http://winklermarkus.at/appconnection.php");
 httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
 HttpResponse response = httpclient.execute(httppost);
 HttpEntity entity = response.getEntity();
 is = entity.getContent();
   }catch(Exception e){
     Log.e("log_tag", "Error in http connection"+e.toString());
   }

The Code of the .php file is here:

$sql_pw = "SELECT ". "Passwort ". "FROM ". "benutzerdaten ";
    $result_pw = mysql_query ($sql_pw); 
    $data_pw = mysql_fetch_array ($result_pw);
    $pw = $data_pw["Passwort"];

    $sql_benutzer = "SELECT ". "Email ". "FROM ". "benutzerdaten ";
    $result_benutzer = mysql_query ($sql_benutzer); 
    $data_benutzer = mysql_fetch_array ($result_benutzer);
    $benutzer = $data_benutzer["Email"];

print(json_encode($pw));
print(json_encode($benutzer));

mysql_close();
?>

as Perception mentioned, I don’t get valid JSON output, could this possibly be in relation with me, trying to transmit 2 strings at once?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T18:32:14+00:00Added an answer on June 15, 2026 at 6:32 pm

    Your PHP code is not doing what you think it’s doing. I cannot recommend a fix to it as you’ve created a significant security hole.

    As an alternative strategy, instead of sending all the passwords and all the emails to the client (in an unassociated fashion no less), send the clients hashed password and email to the service (over SSL). Then on the service side query if you have the combination of email/pass in the database. If you do return login success, otherwise return login failed.

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