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Home/ Questions/Q 8593395
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T23:58:44+00:00 2026-06-11T23:58:44+00:00

I’m trying to read a very large input as String and then converting it

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I’m trying to read a very large input as String and then converting it into long as per follows:[The program works for short input]

The input is two int separated by a space, example: "1248614876148768372675689568324619856329856295619253291561358926935829358293587932857923857934572895729511 413241"

My Code:

import java.io.*;
import java.math.*;
import java.util.*;
public class Solution {
    public static void main(String args[] ) throws Exception {
        Solution obj = new Solution();
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int T = Integer.parseInt(br.readLine());
        String input[]=new String[T];
        for (int i=0;i<T;i++) {
            input[i] = br.readLine();
            }
        for (int i=0;i<T;i++){
            StringTokenizer st = new StringTokenizer(input[i]," ");
                BigInteger N = new BigInteger(st.nextToken());
                BigInteger P = new BigInteger(st.nextToken());
                System.out.println(obj.result(N,P));
            }
        }
    }

    public BigInteger result(BigInteger N, BigInteger P){
        BigInteger temp=1;
        BigInteger c=0;
        for (BigInteger i=0;i<=N;i++){
            //System.out.println(nck(N,i));
            if ((nck(N,i)%P) ==0)
                c++;
        }
    return c;
    }

    public BigInteger nck(BigInteger N, BigInteger k){
        if (k==0)
            return 1;
        else {
            BigInteger temp=1;
            BigInteger y=1;
            BigInteger z=N;
                while(k>=1){
                temp=temp*z/y;
                y++;
                z--;
                k--;
            }
        return temp;
        }
    }
}

I’m getting a java.lang.NumberFormatException

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T23:58:46+00:00Added an answer on June 11, 2026 at 11:58 pm

    You can’t parse this string into a long, it’s too great (greater than Long.MAX_VALUE), you need BigInteger :

    BigInteger bi = new BigInteger(st.nextToken());
    

    Following your edit :

    Don’t try to iterate over a bigInteger : if it’s too great to fit in a long, the loop will be too long for your time. Compare it with a reasonable limit and if it’s smaller, then get it as int and enter your loop:

        BigInteger MAX = new BigInteger("1000000");
        if (bi.compareTo(MAX)<0) {
            int N = bi.intValue();
            for (int i=0; i<N; i++) {
                Test...
            }
        }
    
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