Question

I’m trying to refer to a variable that’s made up from a string, so say $type = "pistol", then:

if ($number > $($type. "s_XP")) 

would be

if ($number > $pistols_XP) 

Obviously the top one isnt correct syntax, because I don’t know how it should be written.
Any help?

Answer 1

The correct syntax would be:

if ($number > ${$type . "s_XP"}) 

However, you should be storing this data in an object instead (or perhaps an array):

$pistol = new Weapon(50);
$nuke = new Weapon(9001);

$type = $pistol;

if($number > $type->XP)