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Home/ Questions/Q 8531425
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T09:28:50+00:00 2026-06-11T09:28:50+00:00

I´m trying to remove a div with jquery but I don´t know how can

  • 0

I´m trying to remove a div with jquery but I don´t know how can I refer to the ID because it´s a PHP var: id=”delete$count”

My Javascript code:

 <script type="text/javascript">
 function deleteFile(fname,directory)
 {
 $.ajax({ url: "delete_img.php",
    data: {"file":fname,"directory":directory},
    type: 'post',
    success: function(output) {
      alert(output);

    $('div').remove();
             }
     });
   }
  </script>

My PHP code:

     $count=1;
     echo '<div class="gallery-item" id="delete$count"></div>';
     echo "<div><a class='ico ico-delete' rel='9' rev='2' href='#'onclick='deleteFile(\"$file\",\"$directory\")'>
    </a></div>";                    
    $count++;               
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T09:28:51+00:00Added an answer on June 11, 2026 at 9:28 am

    I think the below will send delete$count verbatim to the response stream without evaluating $count

    echo '<div class="gallery-item" id="delete$count"></div>';
    

    Change it to

    echo "<div class='gallery-item' id='delete$count'></div>";
    

    so as for PHP to interpolate $count.

    Try then passing this as a third parameter to your function as

    echo "<div><a class='ico ico-delete' rel='9' rev='2' href='#'onclick='deleteFile(\"$file\",\"$directory\",\"delete$count\")'>
    

    and collect its value in a third argument to

    function deleteFile(fname,directory, deletecount) {  }
    

    and replace

    $('div').remove();
    

    by $('#' + deletecount).remove();

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