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Home/ Questions/Q 285625
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:33:48+00:00 2026-05-12T05:33:48+00:00

I’m trying to remove properties with multi values, from RDF and it seems about

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I’m trying to remove properties with multi values, from RDF and it seems about this RDF, I should make below code for removing includeResource:

<Ontologyowl:StudyList rdf:about="stdl827181">
        <Ontologyowl:title rdf:datatype="http://www.w3.org/2001/XMLSchema#string">Basic learning materials</Ontologyowl:title>
        <Ontologyowl:includeResource>
            <Ontologyowl:LearningResource rdf:about="res298830"/>
        </Ontologyowl:includeResource>
        <Ontologyowl:includeResource>
            <Ontologyowl:LearningResource rdf:about="res323717"/>
        </Ontologyowl:includeResource>
    </Ontologyowl:StudyList>

StudyList_ stdl = (StudyList_)rdfDoc.GetIndividual(stdlId, StudyList.Uri, false);
LearningResource[] lrnRes = stdl.includeResources;

        foreach (LearningResource i in lrnRes)
        {
            stdl.RemoveincludeResource(i);
            rdfDoc.RemoveProperty(...);
        }

But I don’t now about rdfDoc.RemoveProperty(..) inputs. Any help about this please?

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:33:48+00:00Added an answer on May 12, 2026 at 5:33 am

    rdfDoc.RemoveProperty(subject, predicate, object) actually requires you to specify the full triple. This method is wrapped by your stdl.RemoveincludeResource(i) method. However, your wrapping method is easier to read and is typesafe. The host C# object (stdl) is the subject, the method (RemoveincludeResource) represents the predicate, and the input parameter (i) will be the object. These items are passed on to the RdfDocument.RemoveProperty method internally. There is no need to call both methods!

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