Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8974243
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T18:38:15+00:00 2026-06-15T18:38:15+00:00

I’m trying to replicate the behaviour of CUDA’s __synchtreads() function in Ruby. Specifically, I

  • 0

I’m trying to “replicate” the behaviour of CUDA’s __synchtreads() function in Ruby. Specifically, I have a set of N threads that need to execute some code, then all wait on each other at mid-point in execution before continuing with the rest of their business. For example:

x = 0

a = Thread.new do
  x = 1
  syncthreads()  
end

b = Thread.new do 
  syncthreads()
  # x should have been changed
  raise if x == 0
end

[a,b].each { |t| t.join }

What tools do I need to use to accomplish this? I tried using a global hash, and then sleeping until all the threads have set a flag indicating they’re done with the first part of the code. I couldn’t get it to work properly; it resulted in hangs and deadlock. I think I need to use a combination of Mutex and ConditionVariable but I am unsure as to why/how.

Edit: 50 views and no answer! Looks like a candidate for a bounty…

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T18:38:16+00:00Added an answer on June 15, 2026 at 6:38 pm

    Let’s implement a synchronization barrier. It has to know the number of threads it will handle, n, up front. During first n – 1 calls to sync the barrier will cause a calling thread to wait. The call number n will wake all threads up.

    class Barrier
      def initialize(count)
        @mutex = Mutex.new
        @cond = ConditionVariable.new
        @count = count
      end
    
      def sync
        @mutex.synchronize do
          @count -= 1
          if @count > 0
            @cond.wait @mutex
          else
            @cond.broadcast
          end
        end
      end
    end
    

    Whole body of sync is a critical section, i.e. it cannot be executed by two threads concurrently. Hence the call to Mutex#synchronize.

    When the decreased value of @count is positive the thread is frozen. Passing the mutex as an argument to the call to ConditionVariable#wait is critical to prevent deadlocks. It causes the mutex to be unlocked before freezing the thread.

    A simple experiment starts 1k threads and makes them add elements to an array. Firstly they add zeros, then they synchronize and add ones. The expected result is a sorted array with 2k elements, of which 1k are zeros and 1k are ones.

    mtx = Mutex.new
    arr = []
    num = 1000
    barrier = Barrier.new num
    num.times.map do
      Thread.start do
        mtx.synchronize { arr << 0 }
        barrier.sync
        mtx.synchronize { arr << 1 }
      end
    end .map &:join;
    # Prints true. See it break by deleting `barrier.sync`.
    puts [
      arr.sort == arr,
      arr.count == 2 * num,
      arr.count(&:zero?) == num,
      arr.uniq == [0, 1],
    ].all?
    

    As a matter of fact, there’s a gem named barrier which does exactly what I described above.

    On a final note, don’t use sleep for waiting in such circumstances. It’s called busy waiting and is considered a bad practice.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I need a function that will clean a strings' special characters. I do NOT
I have a small JavaScript validation script that validates inputs based on Regex. I
I have a French site that I want to parse, but am running into
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I'm trying to convert HTML to plain text. I get many &\#8217; &\#8220; etc.
I'm trying to create an if statement in PHP that prevents a single post
I have thousands of HTML files to process using Groovy/Java and I need to
I am trying to loop through a bunch of documents I have to put
I have a .ini file as follows: [playlist] numberofentries=2 File1=http://87.230.82.17:80 Title1=(#1 - 365/1400) Example

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.