Question

Im trying to request https://www.googleapis.com/pagespeedonline/v1/runPagespeed?url=%5Bhttp://www.my-website.dk/%5D&key=%5Bmy-key%5D using urlfetch from app engine but it’s not working.

When I access it and hardcode my-url into the request like this: https://www.googleapis.com/pagespeedonline/v1/runPagespeed?url=http://www.my-website.dk/&key=%5Bmy-key%5D it’s working fine, but when I use urlfetch.fetch(“https://www.googleapis.com/pagespeedonline/v1/runPagespeed?url=%s&key=%5Bmy-key%5D”, “http://www.my-website.dk”) it’s not working, I have also tried:

page_content = urlfetch.fetch(
        url="https://www.googleapis.com/pagespeedonline/v1/runPagespeed",
        payload=params,
        method=urlfetch.GET
      )

and then serving the parameters in the payload like this:

params = urllib.urlencode({
        "url": page.link,
        "key": "[my-key]"
      })

but the result is the same, it’s not working and the service gives me HTTP status code 400. I also tried adding urlfetch.fetch(u(“http://…”, page.link) but the result is the same.

I edited the code based on the reply from systempuntoout incase any one should run into the same problem:

params = urllib.urlencode({
        "url": page.link,
        "key": "AIzaSyAFpm6W_OmjQl33JC98mAPkvrdGmrR0i4Y"
      })

      page_content = urlfetch.fetch("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?%s" % params)

Answer 1

First, the urlfetch call has an error because you are passing two parameters to the function.
You should use the % between the two strings to pass just one url parameter to the function.

urlfetch.fetch("https://www.goo..e/v1/runPagespeed?url=%s&key=[my-key]" %
                                               "http://www.my-website.dk")

Then, have you tried to urlencode the second url?

import urllib
your_url = {'url': 'http://www.my-website.dk/&key=[my-key]'}
urlfetch.fetch("https://www.g../v1/runPagespeed?%s" % urllib.urlencode(your_url))