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Home/ Questions/Q 4626064
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T03:21:51+00:00 2026-05-22T03:21:51+00:00

I’m trying to retrieve all the data id from a database where their tags(array)

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I’m trying to retrieve all the data id from a database where their tags(array) is like a given value.
This is what I have done so far…

$new_string = 'nice phone';
$construct = mysql_query("SELECT tag_array, name, id FROM details 
WHERE tag_array LIKE $new_string%")
or die("<p>died 20: $construct<br>" . mysql_error());

while($getThis = mysql_fetch_array($construct)){
echo $getThis['id'].'<br />';
echo stripslashes($getThis['name']).'<br />';
}

It doesn’t work ATALL.
Could you please point me to the right direction?
I’m really struggling!!

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  1. Editorial Team
    Editorial Team
    2026-05-22T03:21:52+00:00Added an answer on May 22, 2026 at 3:21 am

    You should put $new_string in quotes.

    NOTE It is very bad practice and you should always escape all variables you are passing to SQL. You should really read up on SQL injection and other security issues.

    Also if you want to match $new_string anywhere in tag_array (which you most likely want), you need to add dollar sign in front of it too. You can read up more at MySQL reference manual.

    So in the end:

    "SELECT tag_array, name, id FROM details WHERE tag_array LIKE '%" . mysql_real_escape_string($new_string) . "%'"
    
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