Question

I’m trying to return an iterator for a vector in a templated class (I’m not sure if that makes a difference, but I’ve read that may, so I thought I’d mention it). The problem is that I get an error about C++ not supporting default-int when I try this. I’ve looked online and from what I can see in forums and explanaions, I don’t think I’m that far off, it just won’t compile.

template<class T> class Table { public:   ...    vector<shared_ptr<vector<T>>>::iterator GetRowIterator();   //vector<shared_ptr<vector<CellValueType> > >::const_iterator GetRowIterator();    ... protected:    vector<shared_ptr<vector<CellValueType> > > data;  //outside vector is rows, inside vector is columns    ... };  vector<shared_ptr<vector<T> > >::const_iterator Table<T>::GetRowIterator() {   return data.begin(); } 

The errors that I get are:

error C2146: syntax error : missing ';' before identifier 'GetRowIterator'  error C4430: missing type specifier - int assumed. Note: C++ does not support default-int    

Edit:
Changed the end angle brackets so they are not as close together – same error.

Any thoughts as to why this is occurring?
As always, thanks for advice/help in advance!

Answer 1

Also remember to use typename when declaring the template-dependent return type:

typename vector< shared_ptr< vector< T > > >::iterator GetRowIterator(); 

and the method definition

typename vector< shared_ptr< vector< T > > >::const_iterator Table<T>::GetRowIterator() {   return data.begin(); } 

Notice also that when defining a template class method outside the class definition, you have to use the template keyword:

template <class T> typename vector< shared_ptr< vector< T > > >::const_iterator Table<T>::GetRowIterator()     {       return data.begin();     } 

So that the compiler can know what the T is about.