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Home/ Questions/Q 586753
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T15:08:23+00:00 2026-05-13T15:08:23+00:00

I’m trying to rotate a bitmap 90 degrees using the following function. The problem

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I’m trying to rotate a bitmap 90 degrees using the following function. The problem with it is that it cuts off part of the image when the height and width are not equal.

Notice the returnBitmap width = original.height and it’s height = original.width

Can anyone help me solve this issue or point out what I’m doing wrong?

    private Bitmap rotateImage90(Bitmap b)
    {
        Bitmap returnBitmap = new Bitmap(b.Height, b.Width);
        Graphics g = Graphics.FromImage(returnBitmap);
        g.TranslateTransform((float)b.Width / 2, (float)b.Height / 2);
        g.RotateTransform(90);
        g.TranslateTransform(-(float)b.Width / 2, -(float)b.Height / 2);
        g.DrawImage(b, new Point(0, 0));
        return returnBitmap;
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T15:08:23+00:00Added an answer on May 13, 2026 at 3:08 pm

    What about this:

    private void RotateAndSaveImage(String input, String output)
    {
        //create an object that we can use to examine an image file
        using (Image img = Image.FromFile(input))
        {
            //rotate the picture by 90 degrees and re-save the picture as a Jpeg
            img.RotateFlip(RotateFlipType.Rotate90FlipNone);
            img.Save(output, System.Drawing.Imaging.ImageFormat.Jpeg);
        }
    }
    
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