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Home/ Questions/Q 7506897
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T22:22:48+00:00 2026-05-29T22:22:48+00:00

I’m trying to rotate an array such that given a number and an array,

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I’m trying to rotate an array such that given a number and an array, rotate the array by that amount. IE:

abcdefgh

given 3:

fghabcde

What is the best way to do this without using additional data structures/minimal space?

Here is a function header:

public static char[] rotateString(char[] s, int rotateAmount){

}
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  1. Editorial Team
    Editorial Team
    2026-05-29T22:22:49+00:00Added an answer on May 29, 2026 at 10:22 pm

    Firstly, I will make a big assumption that “better” means “I do not want any/as few new data structures”.

    If this is the case, then the simplest solution is the best, since I don’t need to bother optimising by time. I know that the other solutions are much more elegant, I’ve only posted it because I’ve read the question as “make sure it’s minimal space-wise”.

    private static String rotate( final char[] a, final int n ) {
        for(int i = 0; i < n; i++) {
            char tmp = a[a.length-1];
            for(int j = a.length-1; j >= 0; j--) {
                a[j] = j == 0 ? tmp : a[(j-1+a.length)%a.length];
            }
        }
        return new String(a);
    }
    

    So I hacked this out pretty quickly. Basically, I’m just doing rotates by lengths of one until I’ve rotated n number of times. To optimise it you probably could take gcd(n, a.length).

    Now, since my solution is pretty terrible, I’ll also post the following code taken from here

    void reverse_string(char* str, int left, int right) {
      char* p1 = str + left;
      char* p2 = str + right;
      while (p1 < p2) {
        char temp = *p1;
        *p1 = *p2;
        *p2 = temp;
        p1++;
        p2--;
      }
    }
    
    void rotate(char* str, int k) {
      int n = strlen(str);
      reverse_string(str, 0, n-1);
      reverse_string(str, 0, k-1);
      reverse_string(str, k, n-1);
    }
    

    This is, what I assume to be a C-style implementation that runs faster than mine, using a basic idea that with three reverses, you can implement an inline shift.

    As is said here,

    The trick is to do three reverse operation. One for the entire string, one from index 0 to k-1, and lastly index k to n-1. Magically, this will yield the correct rotated array, without any extra space! (Of course, you need a temporary variable for swapping).

    I haven’t verified this property on the blog I’ve linked to, so I will post it with a grain of salt that it would appear to work but I’ve never tested it myself…

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