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Home/ Questions/Q 693697
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T02:46:49+00:00 2026-05-14T02:46:49+00:00

I’m trying to send messages generated by Google Protocol Buffer code via a simple

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I’m trying to send messages generated by Google Protocol Buffer code via a simple HTTP scheme to a server. What I have currently have implemented is here (forgive the obvious incompletion…):

 HttpClient client = new DefaultHttpClient();
 String url = "http://192.168.1.69:8888/sdroidmarshal";
 HttpPost postRequest = new HttpPost(url);

 String proto = offers.build().toString();
 List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
 nameValuePairs.add(new BasicNameValuePair("sdroidmsg", proto));

 postRequest.setEntity(new UrlEncodedFormEntity(nameValuePairs));

 try {
   ResponseHandler<String> responseHandler = new BasicResponseHandler();
   String responseBody = client.execute(postRequest, responseHandler);

 } catch (Throwable t) {

 }

I’m not that experienced with communications over the internet and no more so with HTTP – while I do understand the basics… So my question, before I blindly develop the rest of the application around this, is whether or not this is particularly efficient? I ideally would like to keep messages small and I assume toString() adds some unnecessary formatting.

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  1. Editorial Team
    Editorial Team
    2026-05-14T02:46:50+00:00Added an answer on May 14, 2026 at 2:46 am

    Message.toString() prints out the textual (non-serialized) representation. You probably want to use ToByteString() or ToByteArray() to get the serialized version, which you can then pass to your URLencoder.
    Of course, that will incur some overhead for URL encoding. If you can handle multipart/form-data style POSTs, then you can just attach the bytes directly as a file-part, with application/octet-stream MIME-type; that way you’ll be sending the smallest possible message, and won’t have to worry about URL encoding / decoding on either end.

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