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Home/ Questions/Q 7884141
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T04:43:07+00:00 2026-06-03T04:43:07+00:00

I’m trying to set up a set of select boxes to quickly filter fairly

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I’m trying to set up a set of select boxes to quickly filter fairly large datasets into usable chunks. And I’m very close, but receiving the exact opposite of the solution I want, whether or not I use .not() selector (or take it out), or set up the call using .attr= (or .attr!=).

Here’s a fiddle so you can see what’s going on:

http://jsfiddle.net/yD5cG/3/
(Ignore the fact that once you change the top-level selection, the bottom select box doesn’t change. I won’t need to worry about this).

I’ve trawled the site and found a lot of code that’s close to what I need, but I think parsing arrays is throwing it off? At this point, I can’t tell if I’m over-complicating things or over-simplifying. (This is basically an attempt at a simple many-to-many filter using JQuery).

Thanks for anything, even the most basic idea…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T04:43:08+00:00Added an answer on June 3, 2026 at 4:43 am

    Proof: http://jsfiddle.net/iambriansreed/KBKEV/

    var options = $('#selectbox2').html();
    //store original options
    $("#selectbox1").change(function() {
        var selected = this.value.split(',');
        // get selected value and make it an array
        $('#selectbox2').html(options);
        // reset the box to the original options
        $('#selectbox2 option').filter(function(){
            if(this.value.indexOf(',') == -1){
                // simple single values
                return $.inArray(this.value, selected) == -1;
            }else{  
                // check each value
                var values = this.value.split(',');
                for(i in values){
                    if($.inArray(values[i], selected) > -1)
                        return false;            
                }
                return true;  
            }  
        }).remove();    
        // remove any options not in the array of selected values
    });​
    

    A working fiddle and a step by step explanation. Another quality answer.

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