Question

I’m trying to set up a web service.

My approach has been:

• create Dynamic Web Project

• create class “MyService”:

  @WebService
  @XmlSeeAlso({B.class})
  public class MyService {
      public A method() {
          return new B();
      }
  }
  

• create class “A”:

  @XmlSeeAlso(B.class)
  public class A {
      public int propertyOfA=0;
  }
  

• create class “B”:

  public class B extends A {
      public int propertyOfB=1;
  }
  

• Create Web Service from MyService.java

There are no errors, all the files get created. However, the class B does not appear anywhere in the WSDL. Consequently, all web service responses never contain any values for propertyOfB, as it’s not in the service description.

How do I get B into the WSDL?

edit: I’m not sure if it makes any difference, but I’m creating the web service for Tomcat v7.0, Apache Axis

Answer 1

I think your requirement is to inform the user of the web service that B type object can also be returned form the method() operation. So what you have to do is adding a entry like this to your service.xml,

 <parameter name="extraClass">B</parameter>

So it will add entries to WSDL mentioning the web service operation will return these kind of object also. So when code-gen happens these are also generated. You can find which class is returned by checking the xsi:type of the response. Please read this blog for further understanding, http://ssagara.blogspot.com/2011/07/how-to-get-best-use-of-axis2-object.html