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Editorial Team
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Asked: 2026-06-05T08:26:44+00:00

I’m trying to setup an indexed view on a table that doesn’t have a

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I’m trying to setup an indexed view on a table that doesn’t have a unique id. It has two unique identifiers that if combined would be unique for it’s row. I’m having trouble actually creating the unique clustered index that the indexed view requires when I found an thread on MSDN that folks all agree it is possible to create a unique clustered index out of 2 columns for a indexed view @ http://social.msdn.microsoft.com/Forums/en/transactsql/thread/f2c99845-3af1-46e8-9b52-363c24988744

But for the life of me, can’t figure out how to create it. I’m rolling with this query, but it doesn’t seem to cut it.

CREATE UNIQUE CLUSTERED INDEX  [PK] ON MyView
(
MyId1, MyId2
)

Error:

The CREATE UNIQUE INDEX statement terminated because a duplicate key
was found for the object name ‘dbo.MyView’ and the index name ‘PK’.
The duplicate key value is (71cd9b68-1a9e-47bc-bc6b-0008b230a6d8,
0e64aa3a-0631-4caf-82d9-73609ee79b19).

The two IDs listed as duplicates are IDs from MyId2.

So, how could I create a unique clustered index here?

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1 Answer

  1. Editorial Team

    Well the error message seems to suggest that there is more than one record where MyId1 = 71cd9b68-1a9e-47bc-bc6b-0008b230a6d8 and MyId2 = 0e64aa3a-0631-4caf-82d9-73609ee79b19.

    I would recommend running a query that selects based only on that criteria and confirming that this only returns one record. If it returns more, then you cannot recreate a UNIQUE constraint on these two columns unless you eliminate the duplicates.

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